After nearly a month of collating normalization of Class XII marks and students’ scores in JEE (Main), the final ranking for admission to the prestigious National Institutes of Technology (NITs) is finally out. Expectedly, the skewed formula has created confusion among students.
If the problem of normalization is not enough, there is also a report of mathematical miscalculation that has resulted in a peculiar situation. A student, Muneet (roll no. 83201759) with Class XII percentile of 99.25 and JEE (Main) percentile of 98.55 got an All India Rank of 15,638, while another, Arjun Suri (roll no. 83207527), with a Class XII percentile of 98.87 and JEE (Main) percentile of 98.04 got a rank of 12,077. Both of them passed Class XII examination from the J&K Board.
Fears that the normalization process would end up distorting rankings seem to be coming true.
For admission to NITs, it was decided to use the JEE (Main) performance and the normalized Board performance in the 60:40 ratio. But after the JEE (Main) results were announced, the JEE Interface Group came up with the novel normalization formula that has put several students at a disadvantage. DU’s 4yr BTech courses no sure ticket to IITs yet
Six courses, including electronics and computer science, in DU, which were earlier BSc (Hons) and have now become BTech under the new four-year UG programme, may not be your direct ticket to IITs. Though DU had said the switch to BTech would make students eligible for MTech courses in technical institutes, IITs say they haven’t even been approached on this by DU and that their senate will have to take a call on this. P 9 Stark difference in the rank of 1 lakh engg aspirants
The normalization formula for admission to the prestigious National Institutes of Technology has created considerable confusion. The formula is as follows: C= 0.6 X Ao + 0.4 X Bfinal, where (Ao) component is aggregate marks obtained by each student in JEE (Main) and Bfinal component corresponds to the Board percentile. The final rank of the student in the JEE (Main) has been decided by C.
The normalization process — decided by the JEE Interface Group for the Class XII marks component — is as follows: 50% of Board marks be normalized by equating percentile among different Boards and anchoring these to All India JEE (Main) percentiles, and 50% be normalized by equating each Board's percentile with JEE (Main) percentile marks of respective Boards. TOI had earlier reported how this formula can create problem. Now, that the result is out, one can see how irrational the normalization has been.
One student who has passed out from Haryana Board with 124 marks in JEE (Main) and 92.5% in Class XII has got 242 marks as component B and finally got a final rank of 18,000 and another student who passed out from the CBSE with 128 marks in JEE (Main) and 67% in Class XII has got the rank 1,50,000. “There is a stark difference in rank of more than a lakh, despite the fact that student with 67% in class XII scored more in JEE (Main),” said an aggrieved parent.
A third student with 92.5% marks in CBSE and 184 marks in JEE (Main) got the final rank as 17,000. “See the difference. With same 92.5% in class XII, but from different boards and wide variation in JEE (Main) score of 60 marks, students are getting almost the similar rank. How can one say the normalization formula is rational?” asked a student.
If the problem of normalization is not enough, there is also a report of mathematical miscalculation that has resulted in a peculiar situation. A student, Muneet (roll no. 83201759) with Class XII percentile of 99.25 and JEE (Main) percentile of 98.55 got an All India Rank of 15,638, while another, Arjun Suri (roll no. 83207527), with a Class XII percentile of 98.87 and JEE (Main) percentile of 98.04 got a rank of 12,077. Both of them passed Class XII examination from the J&K Board.
Fears that the normalization process would end up distorting rankings seem to be coming true.
For admission to NITs, it was decided to use the JEE (Main) performance and the normalized Board performance in the 60:40 ratio. But after the JEE (Main) results were announced, the JEE Interface Group came up with the novel normalization formula that has put several students at a disadvantage. DU’s 4yr BTech courses no sure ticket to IITs yet
Six courses, including electronics and computer science, in DU, which were earlier BSc (Hons) and have now become BTech under the new four-year UG programme, may not be your direct ticket to IITs. Though DU had said the switch to BTech would make students eligible for MTech courses in technical institutes, IITs say they haven’t even been approached on this by DU and that their senate will have to take a call on this. P 9 Stark difference in the rank of 1 lakh engg aspirants
The normalization formula for admission to the prestigious National Institutes of Technology has created considerable confusion. The formula is as follows: C= 0.6 X Ao + 0.4 X Bfinal, where (Ao) component is aggregate marks obtained by each student in JEE (Main) and Bfinal component corresponds to the Board percentile. The final rank of the student in the JEE (Main) has been decided by C.
The normalization process — decided by the JEE Interface Group for the Class XII marks component — is as follows: 50% of Board marks be normalized by equating percentile among different Boards and anchoring these to All India JEE (Main) percentiles, and 50% be normalized by equating each Board's percentile with JEE (Main) percentile marks of respective Boards. TOI had earlier reported how this formula can create problem. Now, that the result is out, one can see how irrational the normalization has been.
One student who has passed out from Haryana Board with 124 marks in JEE (Main) and 92.5% in Class XII has got 242 marks as component B and finally got a final rank of 18,000 and another student who passed out from the CBSE with 128 marks in JEE (Main) and 67% in Class XII has got the rank 1,50,000. “There is a stark difference in rank of more than a lakh, despite the fact that student with 67% in class XII scored more in JEE (Main),” said an aggrieved parent.
A third student with 92.5% marks in CBSE and 184 marks in JEE (Main) got the final rank as 17,000. “See the difference. With same 92.5% in class XII, but from different boards and wide variation in JEE (Main) score of 60 marks, students are getting almost the similar rank. How can one say the normalization formula is rational?” asked a student.
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